One of the example sequences was the ratio of the Fibonacci terms. If \(f_n\) are the Fibonacci terms, then the ratio is \(a_n = \frac{f_{n+1}}{f_n}\text{.}\) I can use the recursive definition of the sequence of Fibonacci terms: \(f_{n+1} = f_{n} + f_{n-1}\text{.}\) In the ratio \(a_n\text{,}\) I can replace the numerator with this recursive definition. Then some algebra lets me determine a recurivse definition for the \(a_n\text{.}\)
\begin{equation*}
\frac{f_{n+1}}{f_n} = \frac{f_n}{f_n} +
\frac{f_{n-1}}{f_n} \implies a_n = 1 +
\frac{1}{\frac{f_n}{f_{n-1}}} \implies a_n = 1 +
\frac{1}{a_{n-1}}
\end{equation*}
Now I have a recursive definition for the sequences of Fibonacci ratios. Recursive definition are problematic for direct calculations of limits, but there is a useful trick for calculating these limits. Let me restate this recurvise definition.
\begin{equation*}
a_n = 1 + \frac{1}{a_{n-1}}
\end{equation*}
The trick is to take the limit of both sides of the equation. On the left, I have the limit that I want to calculate. On the right, I can use the limit laws to take the limit inside the various operations. Then, the limit of \(a_{n-1}\) is also the limit I want to calculate. Let me lable the result of this limit as \(\phi\text{.}\)
\begin{align*}
a_n \amp = 1 + \frac{1}{a_{n-1}}\\
\lim_{n \rightarrow \infty} a_n \amp = 1 +
\frac{1}{\lim_{n \rightarrow \infty} a_{n-1}}\\
\phi \amp = 1 + \frac{1}{\phi} \implies \phi^2 = \phi +
1 \implies \phi^2 - \phi - 1 = 0
\end{align*}
Now I have an equation for the value of the limit. I proceed to solve the equation.
\begin{align*}
\phi \amp = 1 + \frac{1}{\phi} \implies \phi^2 = \phi +
1 \implies \phi^2 - \phi - 1 = 0\\
\phi \amp = \frac{1 \pm \sqrt{1+4}}{2} = \frac{1 \pm
\sqrt{5}}{2} = \frac{1 + \sqrt{5}}{2}
\end{align*}
Via the recursive definition, I’ve managed to calculate the limit. This number \(\phi\) is the celebrated golden ratio, and I’ve proved that the limit of the Fibonacci terms is the golden ratio.